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4.9t^2-24.5t-2=0
a = 4.9; b = -24.5; c = -2;
Δ = b2-4ac
Δ = -24.52-4·4.9·(-2)
Δ = 639.45
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24.5)-\sqrt{639.45}}{2*4.9}=\frac{24.5-\sqrt{639.45}}{9.8} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24.5)+\sqrt{639.45}}{2*4.9}=\frac{24.5+\sqrt{639.45}}{9.8} $
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